# x2-11x+28=0 Solve this Equation

To solve the quadratic equation x^2 – 11x + 28 = 0, you can use the quadratic formula, which is given by:

x = (-b ± √(b^2 – 4ac)) / (2a)

In this equation, a = 1, b = -11, and c = 28. Plugging these values into the formula:

x = (-(-11) ± √((-11)^2 – 4(1)(28))) / (2(1))

x = (11 ± √(121 – 112)) / 2

x = (11 ± √9) / 2

Now, simplify further:

x = (11 ± 3) / 2

This gives you two possible solutions:

1. x = (11 + 3) / 2 = 14 / 2 = 7
2. x = (11 – 3) / 2 = 8 / 2 = 4

So, the solutions to the equation x^2 – 11x + 28 = 0 are x = 7 and x = 4.

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